GANITA PRAKASH · GRADE 8 · PART II · CHAPTER 2
Source Investigations
Think first. Use AI purposefully. Verify always.
Source application figures
The six right triangles on printed page 53 are redrawn with the same data and right-angle relationships. They are numbered here in reading order.
Page 53 — figure 1
Check the missing side
+ = 130; missing length = .
Page 53 — figure 2
Check the missing side
+ = 116; missing length = 2.
Page 53 — figure 3
Check the missing side
− = 81; missing length = 9.
Page 53 — figure 4
Check the missing side
200 − = 100; missing length = 10.
Page 53 — figure 5
Check the missing side
+ 150 = 250; missing length = 5.
Page 53 — figure 6
Check the missing side
− = 1296; missing length = 36.
Rhombus half-diagonals
Schematic, not to scale. Diagonals bisect at right angles; each side is √(12²+35²)=37.
Additional source checks
Printed page 39 — equal legs 3,4,6,8,9
Hypotenuses: 3, 4, 6, 8, 9. One-decimal bounds: , , , , . Square the endpoints to verify each strict bound.
Printed pages 40 and 47 — missing lengths
Isosceles right hypotenuse 10 gives each leg 5. Page 47 Q4 answers: , 4, 12, , /2. For the final case, 1.+3.=14.5=.
Construct areas three and five times an original square
Combine a square of area A with its doubled square of area 2A to obtain 3A. Double the doubled square to obtain 4A, then combine with A to obtain 5A. The required sides are and .
Why is the hypotenuse longest?
Positive legs give =+> and >. Taking positive roots gives c>a and c>b.
Integer rectangles and primitive reduction
Rectangles 3×4, 5×12, 8×15, 7×24 and 12×35 have diagonals 5,13,17,25,37 respectively. Divide every entry of any non-primitive triple by its gcd: dividing the squared equality by that gcd squared yields a primitive triple.
A thread through mathematical history
The textbook places square constructions in Baudhāyana’s Śulba-Sūtra (c. 800 BCE) and connects the theorem’s familiar name with Pythagoras (c. 500 BCE). It attributes the prime-factor argument for √2 to Euclid’s Elements (c. 300 BCE).
It traces Fermat’s seventeenth-century question about higher powers to Andrew Wiles’s 1994 proof. For positive integers x,y,z and integer n>2, xⁿ+yⁿ=zⁿ has no solution. The lotus application comes from Bhāskarāchārya’s Līlāvatī. These notes follow the textbook’s historical framing.
Textbook connection: Ganita Prakash · Grade 8 · Part II · Chapter 2 — The Baudhāyana–Pythagoras Theorem · printed page 53
