CBSE MATHEMATICS • SELECTED CENTRAL & STATE COMPETITIVE EXAMS
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GANITA PRAKASH · GRADE 8 · PART II · CHAPTER 2

THEOREM — Connect the three squares

Think first. Use AI purposefully. Verify always.

DISCOVER

Start with a sketch and a prediction.

In the dissection, which triangle side becomes the side of the combined square? State a relationship between the three square areas.

Try on paper first. Use the model to test your idea before accepting the explanation.

Understand

For a right triangle with perpendicular legs a and b and hypotenuse c, a2 + b2 = c2. The hypotenuse is opposite the right angle. Conversely, if a triangle’s longest side c satisfies this equation, the opposite angle is right.

Key Ideas

a2 + b2 = c2

Never use the theorem for a triangle merely because its drawing looks right-angled.

Visualise

From square areas to the theorem

34c

The right angle is established by perpendicular legs. The side opposite it is c, the hypotenuse.

Method

Establish the right angle and identify the hypotenuse before substituting. Add squared legs to find c; subtract the known leg’s square from c2 to find the other leg. Take the positive square root.

Worked Example

Given

A right triangle with hypotenuse 17 cm and one leg 8 cm.

To Find

Length of the other leg b

Property

82 + b2 = 172.

Solution

  1. b2 = 289 − 64 = 225.
  2. b = 225 = 15; length is positive.

Result

The other leg is 15 cm.

AIMS Method

  1. A — Attempt independently
    Sketch and predict before using a formula.
  2. I — Investigate the idea
    Separate given facts from visual assumptions.
  3. M — Make connections
    Connect area, length, algebra and geometric constructions.
  4. S — Scrutinise your reasoning
    Check each hypothesis and justify the conclusion.

Think first. Use AI purposefully. Verify always.

Focused Practice

A right triangle has legs 5 and 12. Find its hypotenuse.

Continue with Theorem and conditions →

Check & Feedback

Name the known quantities and target, establish the theorem conditions and check your result in the original relationship.

Textbook connection: Ganita Prakash · Grade 8 · Part II · Chapter 2 — The Baudhāyana–Pythagoras Theorem · printed page 46